代码随想录训练营第三十期|第二十一天|二叉树part07|530.二叉搜索树的最小绝对差 ● 501.二叉搜索树中的众数 ● 236. 二叉树的最近公共祖先
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算法结构
530. 二叉搜索树的最小绝对差 – 力扣(LeetCode)
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode() {}
* TreeNode(int val) { this.val = val; }
* TreeNode(int val, TreeNode left, TreeNode right) {
* this.val = val;
* this.left = left;
* this.right = right;
* }
* }
*/
class Solution {
public int getMinimumDifference(TreeNode root) {
List list = new ArrayList();
if (root == null) return 0;
traversal(root, list);
int res = Integer.MAX_VALUE;
for (int i = 1; i < list.size(); i++) {
int dif = Math.abs(list.get(i) - list.get(i - 1));
res = Math.min(dif, res);
}
return res;
}
private void traversal(TreeNode root, List list) {
if (root == null) return;
traversal(root.left, list);
list.add(root.val);
traversal(root.right, list);
}
}
501. 二叉搜索树中的众数 – 力扣(LeetCode)
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode() {}
* TreeNode(int val) { this.val = val; }
* TreeNode(int val, TreeNode left, TreeNode right) {
* this.val = val;
* this.left = left;
* this.right = right;
* }
* }
*/
class Solution {
int max = 0;
Map map = new HashMap();
public int[] findMode(TreeNode root) {
List list = new ArrayList();
traversal(root);
for (Integer n : map.keySet()) {
if (map.get(n) == max) {
list.add(n);
}
}
int[] res = new int[list.size()];
for (int i = 0; i < list.size(); i++) {
res[i] = list.get(i);
}
return res;
}
private void traversal(TreeNode root) {
if (root == null) return;
traversal(root.left);
map.put(root.val, map.getOrDefault(root.val, 0) + 1);
max = Math.max(max, map.get(root.val));
traversal(root.right);
}
}
236. 二叉树的最近公共祖先 – 力扣(LeetCode)
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
class Solution {
public TreeNode lowestCommonAncestor(TreeNode root, TreeNode p, TreeNode q) {
if (root == null || root == p || root == q) return root;
TreeNode left = lowestCommonAncestor(root.left, p, q);
TreeNode right = lowestCommonAncestor(root.right, p, q);
if (left == null && right != null) {
return right;
} else if (left != null && right == null) {
return left;
} else if (left == null && right == null) {
return null;
}
return root;
}
}
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